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5p^2=-18-33p
We move all terms to the left:
5p^2-(-18-33p)=0
We add all the numbers together, and all the variables
5p^2-(-33p-18)=0
We get rid of parentheses
5p^2+33p+18=0
a = 5; b = 33; c = +18;
Δ = b2-4ac
Δ = 332-4·5·18
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-27}{2*5}=\frac{-60}{10} =-6 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+27}{2*5}=\frac{-6}{10} =-3/5 $
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